Python:List, Tuple, Set, Dict

 #tuples-ordered sequences,comma seperated element

tuple1=('ajit',14,17,'singh')

type(tuple1)

tuple1[0]

tuple1[1]

tuple1[-1]

tuple2=tuple1 + (13,19,'Bhagat')

print(tuple2)

#slicing

tuple2[0:4]

#tuples are immutable

tuple3= sorted(tuple2)#only in case of all same variables

print(tuple3)

        #nesting i.e.tuples inside tuple 

nt=('sachin',18,19,'jahir',(14,15,13),(100,101))

nt[4][2]

#list are ordered sequence within[] and are mutuable

list1=[17,15,'rahul',[13,12,'viraT'],(14,101,109)]

list2 = list1.extend([21,29])

print(list1.extend([21,29]))

list1[3]

print(list1)

print(list2)

list1.append([105,106])#to add one element only

print(list1)

#to change just change the element

list1[2]='sachin'

del(list1[4])

print(list1)

"Bhagat Singh".split()

a=[13,11,18,9]

b=a

a[0]='19'

b[0]#if a changes then b also changes

c=a[:]#now on changing a, c will not change

a[0]='21'

print(c)

#sets-unlike lists, tuples they are inordered

#do not record element position and unique element

set1={'a','b','c','d','e','f'}

#list can be converted into set by using set(list)

set1.add('g')

set1.remove('a')

print(set1)

'd' in set1 #we can verify by using'in' commond 

set2={'r','q','s','t','f'}

set3=set1&set2 #it will provide intersection element

print(set3)

set1.union(set2)#it will create for union

set1.issubset(set2)#to check whether subset or not

set1.difference(set2)

set1.intersection(set2)

#dictionaries-includes keys and values, keys are address of values

#key are immutable and uniaue inside ''

dict1={'a':12,'b':15,'c':19,'d':(7,8,9),'e':['r','n',20]}

'b' in dict1

dict1['a']

dict1.keys()

dict1.values()